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Mathematics 13 Online
OpenStudy (anonymous):

MOD . Please Help

OpenStudy (anonymous):

\[\huge \left| x \right|^{2} - \left| x \right| +1 =0 \] The number of real roots of this are

OpenStudy (anonymous):

@mathslover

OpenStudy (anonymous):

@BSwan @jim_thompson5910 @Miracrown

OpenStudy (anonymous):

No solutions

OpenStudy (anonymous):

Answer is 4 sollutions

OpenStudy (anonymous):

I know imaginary roots come from both cases

OpenStudy (anonymous):

Not from the second case

OpenStudy (anonymous):

\[|x|^2-|x|+1=0 \implies -|x|=-1-|x|^2 \implies |x|=1+|x|^2\] \[x = 1+|x|^2 ~ ~ or ~ ~x=-1-|x|^2\] \[-x^2+x-1=0 ~~~~ or ~~~~ x=-1-|x|^2\] You can factor etc, which will lead to no solutions.

OpenStudy (vishweshshrimali5):

Put, |x| = y, then, you get, \[y^2 - y + 1 = 0\] \[\implies y = \cfrac{1 \pm \sqrt{1 - 4}}{2}\] This gives no real root. So, the given equation will not have any real root as @iambatman said.

OpenStudy (anonymous):

\[\begin{align*} |x|^2-|x|+1&=0\\ |x|^2-|x|+\frac{1}{4}+\frac{3}{4}&=0\\\\\\ \left(|x|-\frac{1}{2}\right)^2+\frac{3}{4}&=0\\\\\\ \left(|x|-\frac{1}{2}\right)^2&=-\frac{3}{4} \end{align*}\] To reiterate what everyone else is saying: no real roots.

OpenStudy (anonymous):

Yes got the same thing you all did lol , the answer in the textbook was incorrect

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