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Mathematics 17 Online
OpenStudy (anonymous):

Rationalize the denominator

OpenStudy (anonymous):

\[\frac{ 8x ^{2} }{ \sqrt{3x+12} }\]

OpenStudy (shamim):

just multiply by √(3x+12) both denominator nd numerator

OpenStudy (anonymous):

alright top is \[8x^2\sqrt{3(x+4)}\] and bottom is 3x+12

OpenStudy (anonymous):

but thats not the answer quite yet what next?

OpenStudy (shamim):

wts the result?

OpenStudy (anonymous):

Well after I multiply the top and bottom i got that now whats the next step do i multiply them together?

OpenStudy (shamim):

i think no more steps here

OpenStudy (anonymous):

then your wrong

OpenStudy (anonymous):

it needs to be simplified more so, can you try to figure it out?

OpenStudy (shamim):

if u can tell me the result, then i can try it more

OpenStudy (anonymous):

I get \[24x^3\sqrt{3(x+4)}+12\]

OpenStudy (shamim):

its impossible to get ur result

OpenStudy (shamim):

something wrong with ur result

OpenStudy (anonymous):

you should get \[\sqrt{3(x+4}\]

OpenStudy (shamim):

3x+12=3(x+4)

OpenStudy (anonymous):

the final answer \[\frac{ 8x^2\sqrt{3x+12} }{ 3x+12 }\]

OpenStudy (shamim):

ya its ur final result

OpenStudy (anonymous):

so you were right at first but we only had to leave it at that step

OpenStudy (anonymous):

lets just repost that for future notice \[\frac{ 8x^2 }{ \sqrt{3x+12} } = \frac{ 8x^2\sqrt{3x+12} }{{3x+12} }\]

OpenStudy (shamim):

u can write 3x+12=3(x+4) use root

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