Rationalize the denominator
\[\frac{ 8x ^{2} }{ \sqrt{3x+12} }\]
just multiply by √(3x+12) both denominator nd numerator
alright top is \[8x^2\sqrt{3(x+4)}\] and bottom is 3x+12
but thats not the answer quite yet what next?
wts the result?
Well after I multiply the top and bottom i got that now whats the next step do i multiply them together?
i think no more steps here
then your wrong
it needs to be simplified more so, can you try to figure it out?
if u can tell me the result, then i can try it more
I get \[24x^3\sqrt{3(x+4)}+12\]
its impossible to get ur result
something wrong with ur result
you should get \[\sqrt{3(x+4}\]
3x+12=3(x+4)
the final answer \[\frac{ 8x^2\sqrt{3x+12} }{ 3x+12 }\]
ya its ur final result
so you were right at first but we only had to leave it at that step
lets just repost that for future notice \[\frac{ 8x^2 }{ \sqrt{3x+12} } = \frac{ 8x^2\sqrt{3x+12} }{{3x+12} }\]
u can write 3x+12=3(x+4) use root
Join our real-time social learning platform and learn together with your friends!