An urn contains six red balls, five white balls, and four black balls. Four balls are drawn from the urn at random without replacement. For each red ball drawn, you win $10, and for each black ball drawn, you lose $15. Let X represent your net winnings. Compute E(X), your expected net winnings. E(X) =
the amount you win times the probability you win it
oh actually i see that this will take some work ready?
yes I am
first you need the probability for every event in the sample space there are 5 of them, because you could pick 0 red 4 black 1 red 3 black 2 red 2 black 3 red 1 black 4 red 0 black
okay
we can compute the probability of each of these, and also we need to compute how much money you make for each outcome
when i say "can" i mean "must"
okay, is it not just asking for the winnings... why do I need the probability?
the second part should be easy 0 red 4 black, lose \(4\times 15=\$60\) so \(-60\) for that one
do you know what the question is asking?
net winnings
no
expected winning, not "net winnings"
okay
expected value i like an average what would you expect to win, on average, for one play of the game
1
?
nm
to compute that average, you need to know the probability you win each of the possible amounts you can win now that we know there are 5 possible outcomes, which i listed above, you have to find first how much money you win (or lose) for each of those outcomes
okay
so for red it is $60
what does "for red it is 60" mean?
from your earlier post
do you see above i listed all 5 possible outcomes?
yes I see that and I understand that the we need to do it for the remaining ones as well
right none of those outcomes was "red" 0 red, 4 black, \(\to -60\) the minus sign because you lost
oh okay
1 red, 3 black \(10-45=-35\) so 1 red, 3 black \(\to -35\)
you can do the rest, i will be right back, let me know what you get then we have to compute the probability of each one, i will help with that
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