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Mathematics 15 Online
OpenStudy (anonymous):

An urn contains six red balls, five white balls, and four black balls. Four balls are drawn from the urn at random without replacement. For each red ball drawn, you win $10, and for each black ball drawn, you lose $15. Let X represent your net winnings. Compute E(X), your expected net winnings. E(X) =

OpenStudy (anonymous):

the amount you win times the probability you win it

OpenStudy (anonymous):

oh actually i see that this will take some work ready?

OpenStudy (anonymous):

yes I am

OpenStudy (anonymous):

first you need the probability for every event in the sample space there are 5 of them, because you could pick 0 red 4 black 1 red 3 black 2 red 2 black 3 red 1 black 4 red 0 black

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

we can compute the probability of each of these, and also we need to compute how much money you make for each outcome

OpenStudy (anonymous):

when i say "can" i mean "must"

OpenStudy (anonymous):

okay, is it not just asking for the winnings... why do I need the probability?

OpenStudy (anonymous):

the second part should be easy 0 red 4 black, lose \(4\times 15=\$60\) so \(-60\) for that one

OpenStudy (anonymous):

do you know what the question is asking?

OpenStudy (anonymous):

net winnings

OpenStudy (anonymous):

no

OpenStudy (anonymous):

expected winning, not "net winnings"

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

expected value i like an average what would you expect to win, on average, for one play of the game

OpenStudy (anonymous):

1

OpenStudy (anonymous):

?

OpenStudy (anonymous):

nm

OpenStudy (anonymous):

to compute that average, you need to know the probability you win each of the possible amounts you can win now that we know there are 5 possible outcomes, which i listed above, you have to find first how much money you win (or lose) for each of those outcomes

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so for red it is $60

OpenStudy (anonymous):

what does "for red it is 60" mean?

OpenStudy (anonymous):

from your earlier post

OpenStudy (anonymous):

do you see above i listed all 5 possible outcomes?

OpenStudy (anonymous):

yes I see that and I understand that the we need to do it for the remaining ones as well

OpenStudy (anonymous):

right none of those outcomes was "red" 0 red, 4 black, \(\to -60\) the minus sign because you lost

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

1 red, 3 black \(10-45=-35\) so 1 red, 3 black \(\to -35\)

OpenStudy (anonymous):

you can do the rest, i will be right back, let me know what you get then we have to compute the probability of each one, i will help with that

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