Question

I REALLY NEED HELP ON THIS

Answer 1

Find the magnitude and direction of r+s-u
a.5.4 cm; 133
b.1.1 cm; 133
c.5.4 cm; 358
d.1.1 cm; 358

Answer 2

@hartnn

Answer 3

do you know how to convert polar form to rectangular form ??
\(from ~ r\angle \theta ~ to ~ x+iy\)
?

Answer 4

no i dont

Answer 5

\(\Large x = r \cos \theta \\ \Large y = r \sin \theta \)

so calculate x and y values for all the 3 vectors
r,s,u

Answer 6

so for u would i use \[\cos \theta = \frac{ adjacent }{ hypostenuse }\] ?

Answer 7

for 'u'

theta is already given as 340

just calculate cos 340 and sin 340

Answer 8

cos340= 0.93 ?

Answer 9

correct

so x = 3 cos 340 = 3*0.934 = ...
y = 3 sin 340 = ....

Answer 10

for sin340 i get -0.34

Answer 11

correct
plug in values

Answer 12

x = 3 cos 340 = 3*0.934 = ...
y = 3 sin 340 = 3*(-0.342)

Answer 13

then do same thing for 'r' and 's'

Answer 14

do you think you can show me how to plug in the first one

Answer 15

sure, i will do 'u' completely, then you try 'r' and 's' :)

\(\Large \bar u = 3 \angle 340 \\ \Large x_u = 3 \cos 340 = 2.819 \\ \Large y_u = 3 \sin 340 = -1.026 \\ \Large so, \bar u = 2.819 -i 1.026\)

got this ?

try doing same thing for r and s :)

Answer 16

thank you so much:) once i find them is there something else to do

Answer 17

YES!

you need r+s-u

so do those operations on corresponding real and imaginary parts

Answer 18

like
\(\Large r+s-u = x_r +iy_r + x_s+iy_s -x_u -iy_u \\ \Large =(x_r+x_s-x_u )+i (y_r+y_s-y_u) =... \)