Quick question, just want to clear out something
is it because for a stationary wave to form you need minimum of 2 waves?
@KissMyAxe @ParthKohli @thushananth01
okay same here use mathematics u know that \[\frac{\lambda}{2} \times 1 (loop) = x(wire length)\] \[\lambda = 2x\] Hence \[v = f \lambda\] \[\frac{v}{2x} = f\]-----1 this is the first equation Now you need two loops so form an equation...why dont u try :)
clarify your doubts
@Somy did u try?
yup thnx i originally did speed=frequency* wavelength and i just thought that i'll need 2 waves for stationary wave to form :D
yes i did)
i need 4 loops thats why im getting 2 waves
oh okay :)
Did u get the answer
yes i did) @KissMyAxe
Well i did it like this and it worked: 1 loop frequency is equal to f therefore for two loops it will be 2f :) ratio method
Hey guys :) I just want to know when they say the word 'loop' I don't really know how to imagine the wave to look like, any ideas anyone?
A loop has two nodes and antinodes between the node
@KissMyAxe like the first 1st image in this picture? http://ipodphysics.com/resources/21603.gif
|dw:1402081689327:dw|
lmao
yes
ummm the yes is directed towards? lol
To the burger which Somy drew
ahahahah i see you are hungry @KissMyAxe
thanks
|dw:1402081983372:dw| what you see is a wave of wavelenth lambda, and therre are 2 loops
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