Suppose that a and b vary inversely and that b=5/4 when a=8. Write a function that models the inverse variation and find b when a =15.
@mukushla @mathmale @e.mccormick
well a vary inversely with variations of b, that means you can write:\[a =\frac{k}{b}\]is it clear?
Yes, it is.
can you find constant \(k\)
Don't you do a*b=k?
use the fact that b=5/4 when a=8 :-) and find \(k\)
Ok thank you! So would it be 10? would K equal 10?
Oh wait, did I do this right?
@mukushla ?
@ganeshie8 @Hero ?
ab = k 8(5/4) = k 10 = k Yes, 10 is correct so far.
Ok then do I plug in 15 for a?
Basically, from here you use formula ab = k again This time, k = 10 (still), but a = 15. Input those values then solve for b
Okay thank you, this clears it all up!
You're welcome
So I got b=5/4a
This is when I simplified it, it's just that its asking me to write a function.
You input 15(b) = 10 and ended up with b = 5/4a? How?
It's looking for the function.
At some point though, you got confused.
Oh... that makes sense.
Basically you're suggesting that b = 5/4a is the same as ab = 5/4 You're suggesting that 5/4 = k which isn't true.
The only consistent value is k = 10. You want to include that in your formula. But one thing I notice is, you never solved for b
I didn't?
No. You were supposed to take ab = k (the formula for inverse variation) then input a = 15 and k = 10 15b = 10 Then solve for b Just try doing that please.
So that would mean it's b=10/a! @Hero
Yes, but you still haven't solved for b. That's the formula though
Thank you :) I got .666
b needs to be in fraction form
10/15
b=10/15
In simplified fraction form
Oh! 1/3
Wups 2/3
How did you get from 10/15 to 1/3? Show your work
Yes, correct b = 2/3 and the formula is ab = 10
Simplified by 5, okay thanks for clearing this up @Hero
For some reason this particular topic confuses 90% of students
It's not even that hard
But for some reason I get a little confused sometimes
Thanks again :)
yw
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