If I am given a triangle with all 3 angles but only 1 side length how do I find the other sides?
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OpenStudy (anonymous):
trigonometric identities?
OpenStudy (anonymous):
you can draw height to the triangle
then use basic trigonometry
OpenStudy (phi):
Law of Sines
OpenStudy (anonymous):
How do I use law of sines?
OpenStudy (phi):
write the ratio of sin(A)/opposite side = sin(B)/opposite side
if we label the side opposite angle A as a, (i.e. use lower case letters for the sides) use
\[ \frac{\sin A}{a} = \frac{\sin B}{b} \]
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OpenStudy (anonymous):
Idk what to do after this:\[\frac{ \sin(83) }{ a }=\frac{ \sin(45) }{ b }=\frac{ \sin(52) }{ 12 }\]
OpenStudy (phi):
just do one pair at a time
\[ \frac{ \sin(83) }{ a }=\frac{ \sin(52) }{ 12 } \]
one way is first cross multiply. can you do that ?
OpenStudy (anonymous):
I got a = 15.08?
OpenStudy (phi):
you should get
a= 12*sin(83)/sin(52)= 15.11
OpenStudy (anonymous):
Okay yea I redid it and got that
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OpenStudy (anonymous):
I got 15.08 by rounding
OpenStudy (phi):
ok, now do the other pair
\[ \frac{ \sin(45) }{ b }=\frac{ \sin(52) }{ 12 } \]