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please explain in steps Find the sum of the first 28 terms of the following sequence: -7, -4, -1 . . . 938 1876 134 588
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a1=-7 d=3 \(\large\color{blue}{ \rm a_{n}=a_1+d(n-1)}\) \(\large\color{blue}{ \rm a_{28}=-7+3(28-1)}\)
after you find the a28, \(\large\color{blue}{ \rm (a_1+a_{28}) \times (1/2) \times 28}\)
i tried doing it and got 1330 using s(n)=(2a+(n-1)d)
the guy that helped me told me to use that
28/2(14+(28-1)(-3)
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is that how you do it
I get 74 for a28. and S28=1036
fisrt you have to find a28, *as I told you) and then plug in (a1 and a28) into the sum formula.
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