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Mathematics 8 Online
OpenStudy (anonymous):

Please someone help me, I need to get this done by today. Will give medal and fan. (attached picture)

OpenStudy (anonymous):

for part A, do you have to show the solution? it's easier if you'll use excel

OpenStudy (anonymous):

I just have to find the correlation coefficient of the data

OpenStudy (anonymous):

alright :) so I used excel and plot the graph. Then I used a trend line that will show the correlation determination, r², which is about 0.0017. To get the correlation coefficient,r, just simply get the square root of correlation determination

OpenStudy (anonymous):

not to sound dumb but how do i do that? find the square root of the correlation determination i mean

OpenStudy (anonymous):

\(r^2=0.0017\) is the correlation determination from your data according to our friend, Microsoft Excel :) \(r=\sqrt{0.0017}\) will be the correlation coefficient.

OpenStudy (anonymous):

I got 0.04, is that right?

OpenStudy (anonymous):

\(r=\pm\ 0.04\) is right

OpenStudy (anonymous):

okay now i just need to describe the relationship of the time and velocity of the toy car, any ideas?

OpenStudy (anonymous):

hmm.. to tell you the truth my weakest point is explaining relationships :/ I can help with the math part or the solving part but not the explaining parts but i'll try ! (^_^) Here's the graph maybe it may help us a bit: based from the correlation coefficient, you got \(-0.04\) ( from the choices). Since it is negative, we can say that as the x values(time) increases, the y-values(velocity) decreases. This statement is true because as you can see from the graph, the trend line (red line) is decreasing as the x-axis is increasing.

OpenStudy (anonymous):

okay thank you (: how about part b?

OpenStudy (anonymous):

lol, do you know the formula for slope? acceleration?

OpenStudy (anonymous):

im sorry but i dont remember ):

OpenStudy (anonymous):

alright, i'll make you remember ;) \(\LARGE Slope\ (m)=\frac{y_2-y_1}{x_2-x_1}=\frac{\Delta y}{\Delta x}\) in your case, \(\LARGE Acceleration\ (a)=\frac{v_2-v_1}{t_2-t_1}=\frac{\Delta v}{\Delta t}\) now can you find the slope?

OpenStudy (perl):

if r is near zero, that means there is no correlation

OpenStudy (anonymous):

I had to choose the correlation from a group of numbers so im guessing there has to be one

OpenStudy (anonymous):

but i already got that i just need help in parts b and c

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