The amount of money in an account with continuously compounded interest is given by the formula A = Pert, where P is the principal, r is the annual interest rate, and t is the time in years. Calculate to the nearest tenth of a year how long it takes for an amount of money to double if interest is compounded continuously at 5.2%.
same as the last one
\[\large e^{.052t}=2\] solve for \(t\)
I didn't mean to post the first part. I was searching and then the site wanted me to make an account and auto posted my search
ok do you know how to solve the equation i wrote above?
"no" is a fine answer, i am just asking i can show you if you do not
Is the answer 1.3330?
i doubt it if my money could double at a mere \(5.2\%\) interest in 1.33 years i would be a millionaire by now
well one of the answer choices is 13.3 years, so I was just thinking the decimal would be moved
start with \[\large e^{.052t}=2\] the \(2\) because you are asked how long before it double
write in equivalent logarithmic form as \[.052t=\ln(2)\]
then since you want \(t\) divide by \(.052\) to get \[t=\frac{\ln(2)}{.052}\] and a calculator to finish
I got 19.231
Did I miss a step?
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