Question

Does anyone know the standard way of solving mods

Answer 1

\[\huge \left| 2x-1 \right| - \left| x+2 \right| -\left| x+1 \right| = 50\]

Answer 2

I have a feeling you just troll people on here, after seeing all your questions asked.. IMO

Answer 3

I am serious not trolling

Answer 4

I would believe you once I see a picture of the question from a book.

Answer 5

Does anyone know how to solve this?

Answer 6

What are you talking about??

Answer 7

where do you get these questions from? What is your source?

Answer 8

I create my own questions

Answer 9

Bye.

Answer 10

@dan815 do you know?

Answer 11

@iambatman

Answer 12

No solutions

Answer 13

\[-|x+1|=50+|x+2|-|2x-1|\]

\[x+1=-50-|x+2|+|2x-1| ~~~~or ~~~~ x+1=50+|x+2|-|2x-1|\]

Eliminate the absolute values, etc, etc, etc.

It's just like the problem you had yesterday, do you see where this is going...?

Answer 14

No , I suppose we make a number line and plot them
after each inerval either a mod would be positive or negative
i don't know how to do that

Answer 15

\[|x+2|=-51-x+|2x-1| ~~~ or ~~~ x+1 =50+|x+2|-|2x-1|\]

\[x+2=-51-x+|2x-1| ~~~ or ~~~ x+2=51+x-|2x-1|\]

\[53+2x-|2x-1|=0 ~~~ or ~~~ x+2=51+x-|2x-1|\]

\[or~~~x+1=50+|x+2|-|2x-1|\]

Now we isolate all the terms with |2x-1| to the left side, then multiply both sides by a constant.

\[|2x-1|=2x+53 ~~~ or ~~~x+2=51+x-|2x-1| ~~~ or\]

\[x+1=50+|x+2|-|2x-1|\]

once again eliminate the absolute value

\[2x-1=2x+53 ~~~ or ~~~ 2x-1 = -53-2x ~~~ or x+1=50+|x+2|-|2x-1| ~~~ or\]

\[x+2=51+x-|2x-1|\]

After that all you have to do is isolate x for each expression, and look for a trivial solution. If you do that you get no real solutions.

Answer 16

Oh nice , thanks

Answer 17

Np