I really only need help on Part A, but if someone could clarify all of them, that would be awesome! Please help, I'm up really late trying to finish this and I could really use some sleep. Thanks in advance! ~Micah K. Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4x and y = 2x + 2 intersect are the solutions of the equation 4x = 2x + 2. Part B: Make tables to find the solution to 4x = 2x + 2. Take the integer values of x between -3 and 3. Part C: How can you solve the equation 4x = 2x + 2 graphically?
so you are plotting 4x and 2x+2. so they will be two separate lines. they will cut each other at only one point. that is the only common point of the graphs y=4x and y=2x+2. so that point is the only solution of 4x=2x+2
any confusion regarding part A @micahpkay ??
But how do I explain how the x coordinate where the lines intersect is the solution to the system of equations? I know that it is, but I don't know how or why. These questions are worded very poorly, in my opinion. @Arnab09
in other words, first graph is the solution for y-4x=0.....i second graph is the solution for y-(2x+2)=0........ii only at the point of intersection these two equations satisfy both, because that is the only common point. so, you can subtract (ii) from (i), you are left with -4x+2x+2=0, or 4x=2x+2
you see, that y part is canceled out if you subtract, but you can only subtract when those equations both are satisfied at a point, that is the point of intersection
I get what you're saying, but it's kind of confusing.
what's confusing you? @micahpkay
Your wording, I guess. Wording always confuses me.
okay, give it some time then
Give what some time?
try to understand what i said, and make some research in internet for your clarification
I really hate problems like this.....
When you said "only at the point of intersection these two equations satisfy both," what is 'both?"
both equations are satisfied at that point only, no other point on the graph
Also, I don't get this part: "so, you can subtract (ii) from (i), you are left with -4x+2x+2=0, or 4x=2x+2"
there are two equations numbered i and ii, see above.. Left hand sides and right hand sides are subtracted, so we are left with -4x=2x+2, in the next step you can take 4x in right hand side, 2x+2=4x
Can you write that part out step by step?
y-4x=0 y-(2x+2)=0 we are subtracting left hand side as well as right hand side to take it down to one equation, as both equations are satisfied at the point of intersection. so, y-4x-{y-(2x+2)}=0-0 y-4x-y+2x+2=0 y terms are cancelled out as you can clearly see, so -4x+2x+2=0 4x=2x+2
Okay, thanks a lot!
So is it like this? -4^x + 2^x + 2 = 0 -4^x + 2^x + 2 - 2^x + 2 = 0 - 2^x + 2 -4^x = -2^x + 2 4^x = 2^x + 2
exactly, though get rid of those power signs
Why?
because the given equation does not involve power relation
Yes it does.
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4x and y = 2x + 2 intersect are the solutions of the equation 4x = 2x + 2. can you explain where it has exponential relation?
It didn't copy and paste correctly. Does that affect your answers?
oh, that does not affect, basic concept is same..
Okay.
Can i ask one more question, @Arnab09 ?
yeah, sure
Okay, I'll close this question and post another one so that you can get another medal and so other people who are searching for an answer can find it more easily.
sure
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