Question

MODULUS

Answer 1

\[\huge \left| \left| x \right| -1\right| < \left| 1-x \right|\]
The set of all sollutions of x belongs to R is

Answer 2

dint u solve that with @ganeshie8 ?

Answer 3

||x|-1|<|1-x|
(|x| -1 )^2 < (1-x)^2
|x|^2 -2|x|+1<1-2x+x^2 .... but . |x|^2=x^2
|x|>x

Answer 4

Answer is
(-infinity , 0 )

Answer 5

Square both sides... That's it.

Answer 6

|x| > x

x < 0

Answer 7

If mod of x is less than 0
then x<0 is it an identity or somnething

Answer 8

|x| > x

case1 :
x > x
FALSE

case2 :
x < -x
2x < 0
x < 0

Answer 9

Squaring both sides will give you this :

\(\large \boxed{\mathsf{\left(|x| -1\right)^2 < (1-x)^2 \\


x^2 + 1 - 2|x| < 1 + x^2 - 2x \\

\cancel{x^2} + \cancel {1} - 2|x| < \cancel{1} + \cancel{x^2} - 2x \\

-2|x| < -2x } \\

\text{Divide both sides by -2} \\

\mathsf{|x| > x \\

x < 0 } }\)

Answer 10

Got it

Answer 11

http://imgur.com/zAjvU3F

Answer 12

Oh.. it is already mentioned by @BSwan . Sorry, didn't notice.

Answer 13

lol thats hilarious fight ;)

Answer 14

>.>