Question

Can someone give me the simplified form of this?

Answer 1

\[\frac{1}{ \frac{ h }{ \frac{ 1 }{ \sqrt{h ^{2}{+1}}} }+\sqrt{h} }\]

Answer 2

x/(1/y) can be written as xy
similarly first simplify h/(1/sqrt(h^2+1)

Answer 3

could you please show me how? step by step! much better if it has explanation..

Answer 4

simplify denominator first
h/(1/sqrt(h^2+1) can be written as h*sqrt(h^2+1)
\[1/(h*\sqrt{h^2+1}+\sqrt{h)}\]

Answer 5

rationalise nr and dnr with \[h*\sqrt{h^2+1}-\sqrt{h}\]

Answer 6

=\[(h*\sqrt{h^2+1}-\sqrt{h} )/(h^2*(h^2+1)-h)\]

Answer 7

is der any options or answer with u?? @jerwyn_gayo

Answer 8

der r no choices given, just d problem "simplify"

Answer 9

can u give me the final answer for this, base on the process(es0 that u have..

Answer 10

\[(h*\sqrt{h^2+1}-\sqrt{h})/(h^2*(h^2+1)-h)\]

Answer 11

Jerwyn: Glad to help with this, BUT my goal would be to help you arrive at a solution yourself. You seem to be asking for answers without any investment of your own time and effort. I'd suggest you share what you already know about simplifying expressions of this kind and ask questions about the parts you don't understand.

Answer 12

When I look at \[\frac{1}{ \frac{ h }{ \frac{ 1 }{ \sqrt{h ^{2}{+1}}} }+\sqrt{h} }\]

Answer 13

the first thing I think of is that we need to simplify that very messy denominator.

Supposing that we had \[\frac{ 1 }{ \sqrt{a}-\sqrt{b} }\] and wanted to get rid of the square roots in the denominator: we could accomplish this by multiplying both numerator and denominator by \[\sqrt{a}+\sqrt{b}. \]

Answer 14

Try this, please. Does doing so remove the square root operators from the denominator?

Answer 15

thanks.