Ask your own question, for FREE!
Mathematics 19 Online
ganeshie8 (ganeshie8):

Solve in integers : \(\large \dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{12}\)

ganeshie8 (ganeshie8):

\(\large 12x +12 y = xy \)

ganeshie8 (ganeshie8):

@mukushla

ganeshie8 (ganeshie8):

first obvious constraint : 12 | xy

OpenStudy (anonymous):

I thought you have the general solution for the equation you mentioned in the other post ;) i wanted to solve it with another method

ganeshie8 (ganeshie8):

Oh okay :) what is the other method ?

ganeshie8 (ganeshie8):

I have general solution only for `ax+by = c` the xy term is throwing me off :/

OpenStudy (anonymous):

suppose \(x<y\) there are some restrictions on \(x\) and \(y\) , for example \(x\) must be less than 24 and greater than 12

Miracrown (miracrown):

well, let's see if we can get y by itself if we can solve for y = ... then we should be able to come to a better solution

OpenStudy (anonymous):

so u have \(12<x<24\)

Miracrown (miracrown):

so you are right that we get 12x + 12y = xy next

OpenStudy (anonymous):

@Miracrown i see the end of your solution, that will be nicer, neater than mine :-) let us do that and isolate one of the variables

OpenStudy (anonymous):

@ganeshie8 you see, we can put some restrictions on \(y\) also

Miracrown (miracrown):

so the first thing we want to do is solve for y that means we need to get all the y-terms on the same side so we move the x-term to the right hand side and xy to the left hand side: so then we factor out the y and divide |dw:1402136222246:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!