Solve in integers : \(\large \dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{12}\)
\(\large 12x +12 y = xy \)
@mukushla
first obvious constraint : 12 | xy
I thought you have the general solution for the equation you mentioned in the other post ;) i wanted to solve it with another method
Oh okay :) what is the other method ?
I have general solution only for `ax+by = c` the xy term is throwing me off :/
suppose \(x<y\) there are some restrictions on \(x\) and \(y\) , for example \(x\) must be less than 24 and greater than 12
well, let's see if we can get y by itself if we can solve for y = ... then we should be able to come to a better solution
so u have \(12<x<24\)
so you are right that we get 12x + 12y = xy next
@Miracrown i see the end of your solution, that will be nicer, neater than mine :-) let us do that and isolate one of the variables
@ganeshie8 you see, we can put some restrictions on \(y\) also
so the first thing we want to do is solve for y that means we need to get all the y-terms on the same side so we move the x-term to the right hand side and xy to the left hand side: so then we factor out the y and divide |dw:1402136222246:dw|
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