What is the pressure exerted by 100g of oxygen gas in a 20L container at 30.0 C?
Use the Ideal Gas Equation: \[PV = nRT\] P is pressure, V is volume, n is the amount of moles of gas, R is the gas constant, and T is the temperature in Kelvin, in this case.
The constant, R, we will use is 0.08206 L-atm/mol-K. You have to first convert your given temperature to Kelvin. Then, convert the 100g of oxygen to moles of oxygen.
The temperature becomes 303.15 K.
Mhm. Now convert the mass to moles.
6.25 moles
is oxygen diatomic?
Hmm, it might be incorrect. Oxygen exists as a diatomic molecule, O2.
So 3.125 moles?
I would suggest to assume the 100g is of diatomic oxygen. && Yesh, 3.125 moles.
So, now, we can find the pressure of the gas. Go back to the Ideal Gas Equation, solve for P, pressure. Plug in your values.
Parth. ♥
The pressure is 3.89
That's the numerical value, but what are the units?
pascals
Nope. :3 Look back at the gas constant I gave you. Using dimensional analysis, all those things cancel out except one unit.
molar mass of oxygen is 32 grams /mol
We already found the moles of O2. ;3
right, now you just plug in
actually to be more precise, add 273.15 to degrees celsius
P = 3.125 moles * 0.08206 * (273.15 + 30) / 20
pressure will be in atm's i suppose I get 3.88695
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