Question

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

Answer 1

note that parallel lines have the same slope... so try to find the slope first. what is the slope of the equation?

Answer 2

the slope of the equation can be found by putting the equation into slope intercept form which is y=mx+b. m=slope. so, if you change the equation, you get -3y= -4x -12

Answer 3

your slope is -4

Answer 4

so slope = ?

Answer 5

then you can plug in the slope, and the point (-3,4) in 'point-slope form' to find the equation... try :)

Answer 6

your next equation would be -3(4)= -4(-3) -12
all you have to do is now multiply (:

Answer 7

if you put your equation in y = mx + b form, the slope is in the m position
4x - 3y = -12 -- subtract 4x from both sides
-3y = -4x - 12 -- divide both sides bt -3
y = 4/3x + 4
slope is 4/3
A parallel line will have the same slope
now use y = mx + b
slope(m) = 4/3
(-3,4)..x = -3 and y = 4
now we sub
4 = 4/3(-3) + b
4 = - 4 + b
4 + 4 = b
8 = b

so your parallel equation is : y = 4/3x + 8

Answer 8

unless you need it in standard form.....do you ?