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OpenStudy (anonymous):
Wave question is seriously giving me blood pressure now....!!!!!
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OpenStudy (anonymous):
OpenStudy (anonymous):
@Somy
OpenStudy (anonymous):
The answer is marked in red; the problem is we don't know how to look at the question...
OpenStudy (anonymous):
Not sure how to use this equation in this though T= λ/c
OpenStudy (somy):
i understood that the formula used is
\[ \frac{ 1 }{ f } =\frac{ \lambda }{ v } \]
meaning
\[T =\frac{ \lambda }{ v }\]
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OpenStudy (anonymous):
@No.name
OpenStudy (somy):
@thushananth01
OpenStudy (anonymous):
NO IDEA
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
it's ok thanks for your time though :)
@KissMyAxe ....?
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OpenStudy (anonymous):
U sure it is C
OpenStudy (anonymous):
Marking scheme man...=_=
OpenStudy (anonymous):
Got it!
OpenStudy (anonymous):
there are thee wave fronts, which means distance is 3 lambda so apply v = f lambda
\[v = f \lambda\]
OpenStudy (somy):
ehm it's women, no?
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OpenStudy (somy):
waaaaaaaaaaaaait how do u know that its 3?
OpenStudy (anonymous):
thanks @thushananth01 :)
OpenStudy (somy):
owh got it so those lines represent 1 lambda?
OpenStudy (anonymous):
Yes somy
OpenStudy (somy):
i mean from 1 line to another
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OpenStudy (anonymous):
\[c = f \times 3 \lambda\]
\[f = \frac{c}{3 \lambda}\]
\[\frac{1}{t} = \frac{c}{3 \lambda} ----t = \frac{3 \lambda}{c}\]
OpenStudy (anonymous):
Yes
OpenStudy (somy):
yes woman or yes lambda?
OpenStudy (anonymous):
Lambda
OpenStudy (somy):
oh okay noted! :D
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OpenStudy (anonymous):
|dw:1402158022025:dw|
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