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Physics 14 Online
OpenStudy (anonymous):

Wave question is seriously giving me blood pressure now....!!!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

@Somy

OpenStudy (anonymous):

The answer is marked in red; the problem is we don't know how to look at the question...

OpenStudy (anonymous):

Not sure how to use this equation in this though T= λ/c

OpenStudy (somy):

i understood that the formula used is \[ \frac{ 1 }{ f } =\frac{ \lambda }{ v } \] meaning \[T =\frac{ \lambda }{ v }\]

OpenStudy (anonymous):

@No.name

OpenStudy (somy):

@thushananth01

OpenStudy (anonymous):

NO IDEA

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

it's ok thanks for your time though :) @KissMyAxe ....?

OpenStudy (anonymous):

U sure it is C

OpenStudy (anonymous):

Marking scheme man...=_=

OpenStudy (anonymous):

Got it!

OpenStudy (anonymous):

there are thee wave fronts, which means distance is 3 lambda so apply v = f lambda \[v = f \lambda\]

OpenStudy (somy):

ehm it's women, no?

OpenStudy (somy):

waaaaaaaaaaaaait how do u know that its 3?

OpenStudy (anonymous):

thanks @thushananth01 :)

OpenStudy (somy):

owh got it so those lines represent 1 lambda?

OpenStudy (anonymous):

Yes somy

OpenStudy (somy):

i mean from 1 line to another

OpenStudy (anonymous):

\[c = f \times 3 \lambda\] \[f = \frac{c}{3 \lambda}\] \[\frac{1}{t} = \frac{c}{3 \lambda} ----t = \frac{3 \lambda}{c}\]

OpenStudy (anonymous):

Yes

OpenStudy (somy):

yes woman or yes lambda?

OpenStudy (anonymous):

Lambda

OpenStudy (somy):

oh okay noted! :D

OpenStudy (anonymous):

|dw:1402158022025:dw|

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