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Mathematics 14 Online
OpenStudy (anonymous):

what pH is pH 2.6 minus pH 3.0 essentially I need to find out what the pH of Coca Cola (pH 2.6) would be if it were bottled with Still water at pH 7 rather than carbonated water at pH 3...

OpenStudy (perl):

you can use the log definition of ph

OpenStudy (paki):

hey welcome to open study... please your question in the relevant section, so that it may be solved/guided properly... thanks...

OpenStudy (anonymous):

thought this was a math question above all else... forgive me, which section do you suggest?

OpenStudy (anonymous):

Science lol

OpenStudy (anonymous):

Chemistry I guess

OpenStudy (paki):

no chemistry.... it's related to chemistry....

OpenStudy (anonymous):

pH is a mathematical function no? i do not know how to best solve it and chemistry forum brings no takers. (sigh) where might i best go to have this solved if not here or there?

OpenStudy (amtran_bus):

PH=-log[H+] concentration. Your ? is not worded clearly.

OpenStudy (amtran_bus):

7-3=4

OpenStudy (amtran_bus):

@perl can take her from here.

OpenStudy (perl):

@AmTran_Bus I thought you were majoring in chemistry

OpenStudy (anonymous):

thanks for noting limitations in the question. does this help: Volume doesn't matter. Lets say one liter. One liter of regular soda Coca Cola with pH 2.6 made with carbonated water. and then 1 liter containing same flavoring formulation in a neutral pH of still water. I need to find the ph value of the flavor components without taking into the account the pH of the carbonated water itself, which i understand to be around 3.0.

OpenStudy (anonymous):

I know it can't be a straight up a-b=c. pH is a logarithmic value and each number represent 10x more than previous. I just don't know how to calculate it, regrettably even if given proper formula... too many years out of school. But I still need to know the answer. Would anyone be so kind as to help answer?

OpenStudy (perl):

regrettably i cannot answer this, but i think khan academy has the answer

OpenStudy (anonymous):

thanks for taking the time to respond; I appreciate it

OpenStudy (perl):

you dont mind , i may come back to this problem

OpenStudy (anonymous):

thanks. I hope you do...

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