Question

Please solve this:

Answer 1

( [12 (1+h) - 1.86(1+h)^2 ] - 10.14 ) /h

Answer 2

:) YES!

Answer 3

( [12 (1+h) - 1.86(1+h)^2 ] - 10.14 ) /h
= ( 12(1+h) - 1.86 ( 1 +h)(1+h) - 10.14 ) / h

Answer 4

Right. I'm at 12+12H-1.86H^2-3.72H-1.86-10.14

Answer 5

yeppers...can you simplify more for me?

Answer 6

I just dont get this @perl

Answer 7

which part?

Answer 8

How did they get the 6.42?

Answer 9

@perl

Answer 10

You calculated the general average velocity for time [ 1, 1 + h ] in the stuff above

Answer 11

so instead of finding the average velocity on [1,2] directly by doing
[ y(2) - y(1) ] / ( 2 - 1) , you found the general average velocity for any time [ 1, 1+h] .
so h can be any number, like 1 or 2 ,

Answer 12

but how did they get this?
the 8.2-1.8

Answer 13

the advantage of solving the general average velocity is that now you can plug in any value for h

Answer 14

I understand that...but how did they do the first part (1 of 4)???
Because when I solve it, or when we did, we dont get that!!!!

Answer 15

The average velocity on [ 1, 1 + h ] , is

Answer 16

sorry open study crashed

Answer 17

one second reading over

Answer 18

ok i think i made a mistake

Answer 19

=( 12(1+h) - 1.86 ( 1 +h)(1+h) - 10.14 ) / h
= ( 12(1+h) - 1.86 ( 1 + h + h + h^2) - 10.14) / h
= ( 12 + 12h - 1.86( 1 + 2h + h^2) - 10.14 ) / h
= ( 12 + 12h - 1.86 - 3.72h - 1.86h^2 - 10.14) / h
= ( 12 - 1.86 - 10.14 +12h - 3.72h - 1.86h^2) / h
= ( 8.28h - 1.86h^2)/h

Answer 20

do you agree so far?

Answer 21

Yes

Answer 22

=( 12(1+h) - 1.86 ( 1 +h)(1+h) - 10.14 ) / h
= ( 12(1+h) - 1.86 ( 1 + h + h + h^2) - 10.14) / h
= ( 12 + 12h - 1.86( 1 + 2h + h^2) - 10.14 ) / h
= ( 12 + 12h - 1.86 - 3.72h - 1.86h^2 - 10.14) / h
= ( 12 - 1.86 - 10.14 +12h - 3.72h - 1.86h^2) / h
= ( 8.28h - 1.86h^2)/h
= h ( 8.28 - 1.86h) / h
= 8.28 - 1.86h

Answer 23

Can you show me how you get the 8.28?

Answer 24

Nevermind. I see.

Answer 25

Thanks. Got it.

Answer 26

=( 12(1+h) - 1.86 ( 1 +h)(1+h) - 10.14 ) / h
= ( 12(1+h) - 1.86 ( 1 + h + h + h^2) - 10.14) / h
= ( 12 + 12h - 1.86( 1 + 2h + h^2) - 10.14 ) / h
= ( 12 + 12h - 1.86 - 3.72h - 1.86h^2 - 10.14) / h
= ( 12 - 1.86 - 10.14 +12h - 3.72h - 1.86h^2) / h
= ( 0 + 12h - 3.72h - 1.86h^2 ) / h
= (8.28h - 1.86h^2)/h
= h ( 8.28 - 1.86h) / h
= 8.28 - 1.86h

Answer 27

Now I can use the intervals!!!!!

Answer 28

ok so now the average velocity on [ 1 , 1 + h] where h is any number , is equal to
8.28 - 1.68*h.

In particular, if you want the average velocity on [ 1 , 2] , you can put it in the form [ 1 , 1 + 1 ] , so here h = 1

Answer 29

Yes! Yay its nice understanding now.

Answer 30

the average velocity on [ 1 , 1 + h] where h is any number is equal to 8.28 - 1.68*h.

In particular, if you want the average velocity on [ 1 , 2] , you can put it in the form [ 1 , 1 + 1 ] , so here h = 1
, and then plug in h=1 into the formula above. 8.28 - 1.68*1 .

Answer 31

YAY!!!!!! YOU ARE THE BEST!

Answer 32

NOT A PERL, BUT A DIAMOND!

Answer 33

if you wanted the average velocity on [ 1, 4] , what would you do ?

Answer 34

I would so something like 4=1+h so H=3

Answer 35

so we can use our average velocity formula that we found on [ 1, 1 + h ] , here [ 1 , 1 + 3] , so h = 3

Answer 36

right :D

Answer 37

:) :) :) $$$$$$$$$$$ for you!

Answer 38

so now you dont have to keep doing the whole average velocity formula for each new interval, since we found a general formula on [ 1, 1 + h]

Answer 39

and then just pick h appropriately

Answer 40

Thanks so much. You saved my day.