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OpenStudy (anonymous):
voltage - 0.35 V
radiation used = 256.7 nm
Work function =?
OpenStudy (anonymous):
any other clue?
OpenStudy (anonymous):
nope!
OpenStudy (anonymous):
There is a paragraph i extracted numerical values from it
OpenStudy (anonymous):
can i see the paragrph
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OpenStudy (anonymous):
The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage 0.35 V when the radiation 256.7 nm is used. Calculate the work function of the silver metal
OpenStudy (anonymous):
ummm , Can we use the equation
\[\huge eV _{o} = \frac{ 1 }{2 }mv ^{2}_{\max}\]
OpenStudy (anonymous):
e= \[1.6* 10^{-19} C\]
OpenStudy (anonymous):
and then use the Einsteins's photoelectric equation maybe
OpenStudy (anonymous):
you should make equal kinetic energy of the electron to the eV, then you should find the energy of the photon, then subtract kinetic energy from the energy of the photon.
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OpenStudy (anonymous):
yUP
OpenStudy (anonymous):
How can we change volts to joules????
OpenStudy (anonymous):
1ev equals 1.6x10^-19 joule
OpenStudy (anonymous):
1 volt?
OpenStudy (anonymous):
no, 1 electron volt equals 1,6*10^-19 joule
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OpenStudy (anonymous):
@Vincent-Lyon.Fr
OpenStudy (vincent-lyon.fr):
oksuz_ is right, the change in potential energy of the electron is
0.35 eV = 0.35 x 1.6x10\(^{-19}\) J