Ask your own question, for FREE!
Physics 6 Online
OpenStudy (anonymous):

Quantum physics

OpenStudy (anonymous):

voltage - 0.35 V radiation used = 256.7 nm Work function =?

OpenStudy (anonymous):

any other clue?

OpenStudy (anonymous):

nope!

OpenStudy (anonymous):

There is a paragraph i extracted numerical values from it

OpenStudy (anonymous):

can i see the paragrph

OpenStudy (anonymous):

The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage 0.35 V when the radiation 256.7 nm is used. Calculate the work function of the silver metal

OpenStudy (anonymous):

ummm , Can we use the equation \[\huge eV _{o} = \frac{ 1 }{2 }mv ^{2}_{\max}\]

OpenStudy (anonymous):

e= \[1.6* 10^{-19} C\]

OpenStudy (anonymous):

and then use the Einsteins's photoelectric equation maybe

OpenStudy (anonymous):

you should make equal kinetic energy of the electron to the eV, then you should find the energy of the photon, then subtract kinetic energy from the energy of the photon.

OpenStudy (anonymous):

yUP

OpenStudy (anonymous):

How can we change volts to joules????

OpenStudy (anonymous):

1ev equals 1.6x10^-19 joule

OpenStudy (anonymous):

1 volt?

OpenStudy (anonymous):

no, 1 electron volt equals 1,6*10^-19 joule

OpenStudy (anonymous):

@Vincent-Lyon.Fr

OpenStudy (vincent-lyon.fr):

oksuz_ is right, the change in potential energy of the electron is 0.35 eV = 0.35 x 1.6x10\(^{-19}\) J

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!