Question

Simplify square root parenthesis 1 minus cosine theta parenthesis times parenthesis 1 plus cosine theta parenthesis.

|sin Θ|

±cos Θ

±tan Θ

square root cosine theta

Answer 1

\[\sqrt{1 - \cos \theta}* \sqrt{1+\cos \theta}\]

Answer 2

Is that right? When multiplying square root, you can but both factors under the square root, and expand it.
\[\sqrt{(1+\cos \theta)(1 - \cos \theta)}\]

Answer 3

yes that is the right question but I think the awnser is plus or minus cos theta but im not sure

Answer 4

Just expand out what's under the square root. You'll see.

Answer 5

wouldn't the awnser be the squareroot of cos and the squareroot of -cos

Answer 6

Nooo. What did you get when you expanded out the factors. ;-;

Answer 7

Nope. Try again. ;3 Look again at your last step in the FOIL method

Answer 8

1-cosTheta+cosTheta-costhetasquared

Answer 9

Yesh. Now simplify what's under the square root. c: You'll get.
\[\sqrt{1 - \cos^2 \theta}\]
Now, you'll have to use this trig identity:
\[\sin^2 \theta + \cos^2 \theta = 1\]

\[\sin^2 \theta = 1 - \cos^2 \theta\]

Answer 10

so is the awnser A

Answer 11

Let's not get ahead of ourselves now. ;-; Do the final steps.

Answer 12

\[\sqrt{\sin ^{2}}\]

Answer 13

.-. And...yeah lol.
\[\sqrt{x^2} = |x|\]
Therefore,
\[\sqrt{\sin^2 \theta} = |\sin \theta|\]

Answer 14

ok thanks