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Mathematics 84 Online
OpenStudy (anonymous):

Verify the identity. cotx minus pi divided by two. = -tan x

OpenStudy (mathmate):

Use sin(x-pi/2)=cos(x) and consequently cos(x-pi/2)=sin(x-pi)=-sin(x)

OpenStudy (anonymous):

wouldnt you use the sum and difference formula of tan to solve?

OpenStudy (anonymous):

tan(x ± y) - (tan x plus or minus tan y) over 1 minus or plus tan x tan y)

OpenStudy (mathmate):

Yes, that would be shorter!

OpenStudy (anonymous):

would you just use the inverse of the sum and difference formula of tan to find it for cot and then simplify?

OpenStudy (anonymous):

mathmate

OpenStudy (anonymous):

@mathmate

OpenStudy (anonymous):

@ParthKohli could you provide some assistance with this problem if you could

OpenStudy (anonymous):

or if any of the online mathematicians could @jim_thompson5910 @hartnn @jdoe0001 @zepdrix

hartnn (hartnn):

i would still suggest using "Use sin(x-pi/2)=cos(x) and consequently cos(x-pi/2)=sin(x-pi)=-sin(x)" and before that, use cot = cos/sin

OpenStudy (mathmate):

Use of the tan formula involves taking limits (because of tan(-pi/2), which make it a little more messy. Something along the lines of: tan(a+b)=(tan(a)+tan(b))/(1-tan(a)tan(b) =(tan(a)/tan(b)+1)/(1/tan(b)-tan(a)) or cot(a+b)=( 1/tan(b) - tan(a)) / ( tan(a)/tan(b) +1) Set a=x and let b-> -pi/2 cot(x-pi/2) = (0-tan(x)) / ( 0+1) =-tan(x)

OpenStudy (anonymous):

i would like to thank both @hartnn and @mathmate for your help and i appreciate you for taking the time to provide assistance as it is extremely helpful to all of us that you aid.

hartnn (hartnn):

welcome ^_^ happy to help :)

OpenStudy (mathmate):

Glad to be of help! You're welcome! Also thank you for taking the time to show your appreciation.

hartnn (hartnn):

lol, thank you for saying thank you :P

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