Verify the identity. cotx minus pi divided by two. = -tan x
Use sin(x-pi/2)=cos(x) and consequently cos(x-pi/2)=sin(x-pi)=-sin(x)
wouldnt you use the sum and difference formula of tan to solve?
tan(x ± y) - (tan x plus or minus tan y) over 1 minus or plus tan x tan y)
Yes, that would be shorter!
would you just use the inverse of the sum and difference formula of tan to find it for cot and then simplify?
mathmate
@mathmate
@ParthKohli could you provide some assistance with this problem if you could
or if any of the online mathematicians could @jim_thompson5910 @hartnn @jdoe0001 @zepdrix
i would still suggest using "Use sin(x-pi/2)=cos(x) and consequently cos(x-pi/2)=sin(x-pi)=-sin(x)" and before that, use cot = cos/sin
Use of the tan formula involves taking limits (because of tan(-pi/2), which make it a little more messy. Something along the lines of: tan(a+b)=(tan(a)+tan(b))/(1-tan(a)tan(b) =(tan(a)/tan(b)+1)/(1/tan(b)-tan(a)) or cot(a+b)=( 1/tan(b) - tan(a)) / ( tan(a)/tan(b) +1) Set a=x and let b-> -pi/2 cot(x-pi/2) = (0-tan(x)) / ( 0+1) =-tan(x)
i would like to thank both @hartnn and @mathmate for your help and i appreciate you for taking the time to provide assistance as it is extremely helpful to all of us that you aid.
welcome ^_^ happy to help :)
Glad to be of help! You're welcome! Also thank you for taking the time to show your appreciation.
lol, thank you for saying thank you :P
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