What book are these questions from?
?
The osmosis question and halothane-oxygen question
A halothane-oxygen mixture (C2HBrClF3 + O2) can be used as an anaesthetic. A tank containing such a mixture has the following partial pressures: P (halothane) = 170 mmHg and P (O2) = 570 mmHg. If the tank contains 160 g of O2, calculate the mass of C2HBrClF3 present.
The most common kidney stones are formed by the precipitation of calcium oxalate monohydrate (CaC2O4H2O, Ksp = 2.3 x 10-19). A patient suffers from hyperoxaluria such that his urine oxalate concentration is elevated to 3.0 x 10-12 mol dm-3 . If the pH of the urine is 6.0 and the Ca2+ concentration is 3.0 x 10-3 M, will the patient be at risk of forming calcium oxalate monohydrate kidney stones? Justify your answer.
i dont know what book, they're from. you could try to google to find that out. If you want i can help you solve them though
Okay, that would be good. They've come up and I don't have answers.
Especially the osmosis one
The osmotic pressure of blood at 37 oC is 7.65 atm. An energy drink contains 200.0 mg of caffeine (MM 194 amu) and 150.0 mg taurine (MM 125 amu) per 100.0 mL. Calculate the osmotic pressure of the solution and explain whether it is isotonic, hypotonic or hypertonic with blood
I did google it and you're the only one who's mentioned these questions...I can't find the book.
okay, so you want to work on last one? Part of the guidelines is that you only ask one question per thread.
Okay, new here. Wanted to find out where the questions were from so I could find the book solutions.
so find the molarity of the solution with the masses given. plug that into the formula: \(\Pi=MRT\) \(\Pi\) is the osmotic pressure M is molarity R= is the gas constant 0.08602 L*atm/K*mol T is the absolute temperature compare your answer to the osmotic pressure of blood given
And then how do you know if its hypotonic, hypertonic or isotonic?
if it has a higher osmotic pressure than blood, then the solution is hypertonic, if its the same iso-, if it's lower then hypo-.
Thank you!
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