Question

@hartnn could you help me with another that's kind of similar?

Answer 1

sure

Answer 2

\[\large -21 \sqrt{27x^9}\]

Answer 3

I got \[\sqrt {27}=3 \sqrt{3}\]

Answer 4

it is sqrt3

Answer 5

correct
go on
\(\sqrt {x^9} =....\)

Answer 6

\(\sqrt{27} = 3\sqrt 3\) is correct

Answer 7

\[\large \sqrt {x^3} \times \sqrt {x^3}\]

Answer 8

hint :
9 = 8+1

Answer 9

\(\huge \sqrt{x^9} = \sqrt x \sqrt {x^8} = \sqrt x (x^8)^{1/2} =...\)

Answer 10

I'm not sure at all.

Answer 11

\(\Large \sqrt {x^n} = x^{n/2}\)

Answer 12

Okay I understand that sorta

Answer 13

so,
\(\Large \sqrt{x^8 } = (x^8)^{1/2} = x^{8/2} =....\)

Answer 14

Ohh alright
So
x^4?

Answer 15

yes
\(\huge \sqrt{x^9} = \sqrt x (x^8)^{1/2} =x^4 \sqrt x\)

and final answer ?

Answer 16

\[\huge -63x^4 \sqrt {3x}\]

Answer 17

correct! :)

Answer 18

So I have another.
\[\huge -2 \sqrt {243y^3}\]
So I have
\[\huge \sqrt {243}=9 \sqrt{3}\]
Then I have
\[\huge \sqrt {y^3}=\sqrt {y}\sqrt{y^2}=y \sqrt{y}\]
So my final answer will be
\[18y \sqrt{3y}\]
Is that right?

Answer 19

excellent work!
you just missed the negative sign, everything else is correct :)

Answer 20

Oh yeah thanks!

Answer 21

you learn fast :)

Answer 22

I did these a little in alg 1 but that was 4 years ago and couldn't remember too well. Lol. I didn't have to do these in any other math I took for high school so it was hard to remember.