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Mathematics 11 Online
OpenStudy (anonymous):

PLEASE HELP, WILL FAN AND GIVE MEDAL!!!!!! Point G is located at (3, -1) and point H is located at (-2, 3). Find the point that is the distance from point G to point H.

OpenStudy (anonymous):

@sourwing

OpenStudy (jdoe0001):

"Find the point that is the distance from" ^ is there anything missing there?

OpenStudy (jdoe0001):

or you just need how long from G to H?

OpenStudy (jdoe0001):

\(\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ G&({\color{red}{ 3}}\quad ,&{\color{blue}{ -1}})\quad H&({\color{red}{ -2}}\quad ,&{\color{blue}{ 3}}) \end{array}\qquad d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)

OpenStudy (anonymous):

oh its 2/3 the distance, sorry bout that

OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

hmm 2/3 the distance? from G to H? any ideas what that means?

OpenStudy (anonymous):

well we have to find the point where that would be

OpenStudy (anonymous):

OpenStudy (jdoe0001):

|dw:1402179798046:dw| would that be about right?

OpenStudy (anonymous):

i think so but i need the coordinates

OpenStudy (jdoe0001):

would it be fair to say the point P is at a ratio of 2:1 from G to H?

OpenStudy (jdoe0001):

if from say G to P, is 2/3 of the whole line and from P to H is 1/3 only of the whole line then the distance GP will be at a ratio of 2:1, that is, twice as much as the distance PH .... is that fair to say?

OpenStudy (anonymous):

well its asking 2/3 of the distance from G to P so the point would lie on line GP

OpenStudy (anonymous):

@mathslover

OpenStudy (anonymous):

@vishweshshrimali5

OpenStudy (anonymous):

@mathmate

OpenStudy (vishweshshrimali5):

Hi @kd7023s5

OpenStudy (anonymous):

hello..

OpenStudy (vishweshshrimali5):

Okay lets see what do we have ..... okay lets assume the required point be P (x,y). Okay ?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

wait.. i think it was a mistake on my part because @jdoe0001 was right but i just needed the coordinates of point p

OpenStudy (anonymous):

sorry...

OpenStudy (vishweshshrimali5):

its ok

OpenStudy (vishweshshrimali5):

Answer me this would this point P necessarily lie on line GP ?

OpenStudy (anonymous):

yeah

OpenStudy (vishweshshrimali5):

No, its not necessary. See: |dw:1402238160153:dw| (the circle is drawn in such a way that its centre is H and HP is its radius).

OpenStudy (anonymous):

it doesnt look like h is the center..

OpenStudy (anonymous):

my answer was (-0.33, 1.67)

OpenStudy (vishweshshrimali5):

@kd7023s5 please forget my replies. I took the question to a little higher level than required. It would be best if @jdoe0001 helped you out. Sorry

OpenStudy (vishweshshrimali5):

Its just that if you would follow my solution you will get infinitely many such points P.

OpenStudy (anonymous):

youre right but the question is asking for a point on the line

OpenStudy (anonymous):

and its ok, i was right

OpenStudy (vishweshshrimali5):

Yeah I have verified it. Good work

OpenStudy (anonymous):

Did we arrive at the answer?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

okay

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