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how many moles of nitrogen dioxide, NO2, are required to produce 3.56 mol of nitric acid?
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Hi! So I think I know how to solve this problem. I apologize if I'm not correct! I recommend creating a conversions table. So the molecular formula for nitric acid is HNO3. Since we know mols of nitric acid we can convert this from mols to grams of Nitrogen dioxide: 3.56molsHNO3 X (63.02g HNO3 / 1 mol HNO3) X (1 mol NO2/ 46.01 g NO2)
when I multiplied this out it came out with 4.88 mols of NO2
which doesn't seem too bad of a number
Thank you so much!
No prob. Anytime :)
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