Let f(x) = x2 - 81. Find f-1(x). ±square root of the quantity x plus 81 9square root of x 1 over quantity x squared minus 81 x squared over 81
To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
yea i did that but i got confused
I've seen you attempt harder problems, show me where you went wrong :P
this is where i stop at y=5x+12 x=5y+12 x-12/5=5y/5 x-12/5=fx
Wrong problem? y =5x+12?
opps wrong one i got the answer to that one i mean i really didn't start the question i am asking you
Lol well, follow the steps I gave you, and we can see how you do :)
\[f(x) = x^-81 \implies y = x^2-81\]
Do the next step :D
is it C
Jagr I don't understand, it's just simple algebra, I've seen you answer much tougher questions..mhm, and no actually do the problem instead of guessing. Just follow the steps I gave you, I'll help you.
So we have y=x^2-81, next step?
x-81=y^2
No, that's not right, you just replaced the square from x to y, not the variable itself.
THIS is CONFUSING. ok so was i even close
\[y=x^2-81, ~~~ x=y^2-81\] that's all you had to do, don't over complicate it.
oh ok
Now solve for y
x squared over 81
do you square root 81 to 9
\[y = \pm \sqrt{x+81}\]
Now just change the y back to f^(-1)
so its A
@iambatman is it A
Yes it is A.
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