Geometry
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OpenStudy (anonymous):
Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).
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OpenStudy (anonymous):
HELP ASP
OpenStudy (anonymous):
first you create equation of line with given points.
OpenStudy (anonymous):
I just need the answer right now
OpenStudy (anonymous):
then line perpendicular to it have a slope in the form . m*m'=-1. so you can proceed further
OpenStudy (eric_d):
y=-3x+c
@Joseph91
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OpenStudy (anonymous):
i didn't tried the question.But i have given some ideas which will help you to solve the question.
OpenStudy (eric_d):
@mathmale
OpenStudy (anonymous):
It has + and the = as the preset in the beginning
OpenStudy (anonymous):
Here is the question
OpenStudy (anonymous):
@eric_d
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OpenStudy (eric_d):
hang on
OpenStudy (eric_d):
first find midpoint
OpenStudy (eric_d):
then find the gradient, m
OpenStudy (anonymous):
eric i will give you another medal plus a testimonial
OpenStudy (eric_d):
midpoint= (3,-2)
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OpenStudy (eric_d):
gradient,m= -5-1/2-4=3
OpenStudy (anonymous):
Im in a test thats why i need the answer
OpenStudy (eric_d):
since it's perpendicular bisector,
m=1/3
OpenStudy (eric_d):
so,
OpenStudy (eric_d):
y=m(x-a)+b
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OpenStudy (eric_d):
y=1/3(x+3)-2
OpenStudy (eric_d):
y=1/3x-1
OpenStudy (eric_d):
that's the final answer
@fail
OpenStudy (anonymous):
is that the answer ?
OpenStudy (anonymous):
Its not right but its ok
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OpenStudy (eric_d):
but that's what I got
OpenStudy (anonymous):
@eric_d did you see the photo that's how its suppose to be
OpenStudy (eric_d):
yup
I'm nt very sure with that
Try tagging others
but that's what I got
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
@sweetburger