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Mathematics 10 Online
OpenStudy (anonymous):

find dy/dx http://prntscr.com/3q49os

OpenStudy (anonymous):

can you help from (d)

OpenStudy (babalooo):

can't you just multiply together and then take derivative?

random231 (random231):

yeah you can even do that! :)

OpenStudy (babalooo):

this is easier than c in my opinion lol

mathslover (mathslover):

Yeah @babalooo is right. Simplify it @LilySwan - Can you do that?

OpenStudy (anonymous):

i know we have to ue the product rule but at one point i think im messing up so im stucked

mathslover (mathslover):

You are given with : \(y = [50x^4] [20x^8] \) Right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Ganeshie showed you this, just multiply and use power rule.

mathslover (mathslover):

Now, instead of using product rule and making it more complicated. We will follow some basics. We will simplify it a bit.

mathslover (mathslover):

@LilySwan - Ganeshie8 explained you this. Do you want more help? Or did you net get what Ganeshie8 explained?

mathslover (mathslover):

*not.

OpenStudy (anonymous):

\[d/dx(y) = [4(50x^3)][8(20x^7)]\]

OpenStudy (anonymous):

Remember that great table he made for you? Use the product rule.

OpenStudy (anonymous):

Well first multiply it as you normally would, as mathslover requested you should simplify it before taking the derivative.

OpenStudy (anonymous):

i just told that i tried simplifying it but got stuck

mathslover (mathslover):

Okay, show us what you did yet. We will try to help you then.

OpenStudy (anonymous):

I mean, act if you're not going to take the derivative, what would you do if that problem said simplify?

OpenStudy (anonymous):

\[50x^4*20x^8 =?\]

OpenStudy (anonymous):

\[ax^n \times bx^m = (a \times b)^{n+m}\]

OpenStudy (anonymous):

With that said your answer will be?

OpenStudy (anonymous):

1000x^12

OpenStudy (anonymous):

Correct, simple right? Now use the power rule.

OpenStudy (anonymous):

12000^11

OpenStudy (anonymous):

so we should simply be using a power rule here

OpenStudy (anonymous):

That's it, that was the power rule.

OpenStudy (anonymous):

can you help with (e)

OpenStudy (anonymous):

Use the quotient rule

OpenStudy (anonymous):

in the quotient we be using power rule first

OpenStudy (anonymous):

You should go back to ganeshies table, and take a screen shot or write down all the rules, and then you can see how to approach each problem.

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