find dy/dx http://prntscr.com/3q49os
can you help from (d)
can't you just multiply together and then take derivative?
yeah you can even do that! :)
this is easier than c in my opinion lol
Yeah @babalooo is right. Simplify it @LilySwan - Can you do that?
i know we have to ue the product rule but at one point i think im messing up so im stucked
You are given with : \(y = [50x^4] [20x^8] \) Right?
yes
Ganeshie showed you this, just multiply and use power rule.
Now, instead of using product rule and making it more complicated. We will follow some basics. We will simplify it a bit.
@LilySwan - Ganeshie8 explained you this. Do you want more help? Or did you net get what Ganeshie8 explained?
*not.
\[d/dx(y) = [4(50x^3)][8(20x^7)]\]
Remember that great table he made for you? Use the product rule.
Well first multiply it as you normally would, as mathslover requested you should simplify it before taking the derivative.
i just told that i tried simplifying it but got stuck
Okay, show us what you did yet. We will try to help you then.
I mean, act if you're not going to take the derivative, what would you do if that problem said simplify?
\[50x^4*20x^8 =?\]
\[ax^n \times bx^m = (a \times b)^{n+m}\]
With that said your answer will be?
1000x^12
Correct, simple right? Now use the power rule.
12000^11
so we should simply be using a power rule here
That's it, that was the power rule.
can you help with (e)
Use the quotient rule
in the quotient we be using power rule first
You should go back to ganeshies table, and take a screen shot or write down all the rules, and then you can see how to approach each problem.
Join our real-time social learning platform and learn together with your friends!