add any three numbers of the following and answer should be 60 2 , 6, 10, 14, 18, 22, 26, 30, 34, 38, 42, 46, 50, 54, 58
What have you tried so far?
yea tried. but i didnt get
alright, let's start by getting rid of some choices that don't work. :)
k
we need to pick 3 numbers that add up to 60
so could we ever pick 58? or is that going to be too big?
for example, if I pick 58, then the smallest thing I could choose would be 2, but then I'm already at 60 with just two numbers, but I wanted to use three!
So, we can cross off 58 from the list, it can't ever work.
does that make sense?
of course, there's more, but I want to make sure you understand so far. :)
from 2 to 58 any three nos. must be added and answer should get 60. my lecturer gave this question. its like puzzle. im confused
OK, I understand, but do you see that we can never use 58 as one of our numbers? it's too big.
yes
OK, excellent! So we now only need to think about the numbers from 2 to 54. We've made things easier (just a little). :)
So, let's pretend that I pick 54 as my first number... can I pick a second and third number that will work? Or are we still too big?
54 + ? + ? = 60 Can we choose numbers that make this true?
Well, we can't pick 6 for the second number or else 54 + 6 = 60 TOO BIG!
And 2 doesn't work either, 54 + 2 + 2 = 58 TOO SMALL!
So, 54 is impossible :)
not same number
Oh, and there you go, so it's even more impossible!
one number should be used only once
yes i think so.
so cross off 54, it doesn't work :)
Now, we can keep doing this for each of the numbers.
You will find that 50, 46, and 42 do not work.
And neither does 38.
Let's try 34 as the first number.
If we pick 26 as the second we are too big... 34 + 26 = 60 TOO BIG!
yes
So maybe 22? 34 + 22 + ? = 60 means that 56 + ? = 60 ... nope... don't have a 4.
maybe 18? 34 + 18 = 52... nope don't have an 8... AHH!!! A little frustrating right? :)
But, we must be getting closer...
I'm still trying to find the answer too, so the game takes a little bit of time to figure out... :)
hmm... maybe I ruled one out that I shouldn't have...
im trying it n searching on net. still i didnt get
ok, me too :)
it might be an impossible puzzle... there might not be any combinations that work
actually, yes it is not possible to answer this question.... no combination exists.
ok
looks like your lecturer either made a mistake or was just trying to strain your brain. :)
you aren't imagining things though, I worked it out with some algebra and it is impossible as far as I can tell. :)
good work though, you persevered on a very difficult question!
I will post the reason it is impossible below, in case you or anyone else cares to know how I solved it. :)
The question wants three different numbers from the list that sum to 60. In other words, X + Y + Z = 60. Ask yourself, what do the numbers on the list look like? They look like 2, 6, 10, 14, etc. all of which can be calculated by the rule 2 + 4*(some whole number). I will call X = 2 + 4*a, Y = 2 + 4*b, and Z = 2 + 4*c. Where a, b, c are whole numbers. Then, substituting we would need (2 + 4*a) + (2 + 4*b) + (2 + 4*c) = 60 6 + 4*a + 4*b + 4*c = 60 4*a + 4*b + 4*c = 54 4*(a + b + c) = 54 so, a + b + c = 54/4. But 54/4 is 13.5 which is NOT a whole number and it should be since a, b, and c are all whole numbers! Thus, the question is ridiculous and impossible to solve.
may be ur correct. i think my lecturer gave us the brain work.
probably :) it's certainly a good (but very frustrating) exercise.
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