A rock is thrown with an initial vertical velocity component of 30 m/s and an initial horizontal velocity component of 40 m/s.

Question

anonymous · Answer

Can you explain how to solve this problem.

A rock is thrown with an initial vertical velocity component of 30 m/s and an initial horizontal velocity component of 40 m/s.?

a. What will these velocity components be one second after the rock reaches the top of its path? 
b. Assuming the launch and landing heights are the same, how long will the rock be in the air? 
c. Assuming the launch and landing heights are the same, how far will the rock land from where it was thrown?

anonymous · Answer

what do you think?

naveenbabbar · Answer

(a) when the rock reaches to its maximum height, vertical component becomes zero, horizontal component remains same.
(b) As you have said the time to reach the maximum height is one second, then the time of flight is 2 seconds.
(c) The horizontal range will be = time of flight (2s) * Horizontal component (40m/s)= 80m