Medal!! which of the following expressions are equivalent to 2/x^6-y^6 choose all that apply
A
is that the only one?
It shld be
nope. Think of the identity: a^2-b^2 = (a+b)(a-b)
okay, forget.. that formula.. @mathmate :)
I am assuming that you mean\[2/x^6-y^6\rightarrow \frac{ 2 }{ x^6 }-y^6\]
Please verify whether or not this is correct. Food for thought: If you had \[ \frac{ 1 }{ x^6 }-y^6,\]...with no coefficient 2, then this would have the form \[a^2-b^2,\]...which in turn would give you the factors \[(\frac{ 1 }{ x^3 }-y^3)(\frac{ 1 }{ x^3 }+y^3)\] Hope this information is of some help to you in finding your own answer to this question.
@mathmale I'm afraid too many people are not respecting the PEDMAS rules when it comes to linearizing a fraction. The question is meant to be 2/(x^6-y^6) judging from the choice of responses.
@mathmate: Your use of parentheses is a great help. @FearlessRene: please take note how much the simple use of parentheses can do to clarify a math expression.
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