Something i read in a book
@Vincent-Lyon.Fr @naveenbabbar i am wondering what F hg is?? i always thought it was FRICTION.. that allows the horse to move forward
Fhg means the force on the horse by the ground
You are correct. Fhg meaning force applied by the ground on the horse.
see the note.. i don't understand that note.. what reaction force is F hg ?
but where does that force COME FROM?? shouldn't it be FRICTION????? hwat reaction force is that??
It is friction. That is the only force which helps the horse to move.
if the horse had some frictionless legs or something.. he wouldn't be able to move forward.. and the F hc force would pull it towards the cart.. !! so i don't understnad why they call it some crazy reaction force.. instead of calling it friction?? or are they just saying friction acts as the reaction force here?
This is correct. Fhg is the forward force that the ground exerts on the horse thanks to friction. This is a case when friction produces forward acceleration (but, strangely enough, no motive power).
yes i just wantd to confirm that it was friction.. because they didn't mention the word friction :P
If you are considering Fhc the n also consider FCh and both of them are internal forces. Hence in the absence of friction the horse will not be pulled towards the cart. Also from your question I think you have problem with understanding of internal and external forces and the fact that the forces are mutual.
It is. It is part of the reaction of the ground since its value adapts to the effort exerted by the horse.
Horse can't move with out external force, which is friction.
Both the answers are correct and convincing. :D
oh yes in this case it can't @naveenbabbar sorry about that :D but if i imagine.. pulling on the rope (which is connectd to cart).. then i woudl move towards the cart IF friction between my legs and ground was zero.. and if the friction is HIGHER than the pull that I PUT on the cart, only then.. will i be able to pull the cart towards me (while i stay put .. at rest)
Sounds correct.
Then the external force on you will be the tension in the rope.
Yea so that is the example i would wanna give .. to make students understand HOW i stay put and the cart would come towards me.. EVEN though, from newton's third law, cart pulls me back! :D
If the cart is standing on a frictional surface.
@naveenbabbar yes yes.. i get the concept of external and internal forces.. in order to evalulate the acceleration of the system (me and cart).. but i was only talking about the concept of third law and why i would stay put! so in theory .. if i try to push a desk filled with students.. then the desk would weigh a lot.. and thus would have HUGE friction .. so i would have to put huge force.. that is fine.. I CAN PUT THAT FORCE.. but i will not be able to push it because, FRICTION BETWEEN ME and the ground is not enough.. i would wanna give this example with demo in class :D .. its perfect right??
and then.. i would push from the other side (taking the support of the wall) .. and convince .. that i INDEED have enough muscular force.. to push the desk.. what u think @Vincent-Lyon.Fr ?
This is also what I would do to convince them. The strongest man (you or superman), without some solid ground (resp. wall) to apply friction (resp. normal) force is powerless.
:D. .. ok .. then i can show some super man video :D..
The problem is that superman pushes without apparent reaction (wall), more like a rocket.
yea the physics behind that.. is very complicated.. xD.. or may be magical
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