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Biology 12 Online
OpenStudy (anonymous):

5. If two parents are heterozygous for a genetically inherited dominant trait, what is the probability that they will have a child together who has this trait in his or her phenotype? a. 25% b. 50% c. 75% d. 100%

OpenStudy (abhisar):

Hello @ambo15 ! \(\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\\\color{white}{.}\\\Huge\sf\color{blue}{~~~~Welcome~to~OpenStudy!~\ddot\smile}\\\color{white}{.}\\\\\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\)

OpenStudy (abhisar):

It would be 75%

OpenStudy (koikkara):

HopE if U aRe SatisfieD with ThiS AnsweR, PleAsE ClosE ThiS QuestioN !! ThanK YoU !! KeeP In ToucH WitH OpeN StuDy !!

OpenStudy (anonymous):

@ambo15 Let's actually work through this with a Punnett square. T is dominant and t is recessive. Both parents are Tt.|dw:1402269755992:dw| There we go, 3 that are the dominant phenotype and 1 that is recessive. So, 3/1 or 75/25.

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