I am trying to help my son. A canoe travels 4 miles per hour in still water. It travels 6 miles up stream and back again in 4 hours. what is the speed of the current? He got an answer of 5.2 is that correct?
It cannot be correct because 5.2 is greater than 4, so he will never go upstream. Let s= speed of current, then \[\frac{6}{4-s}+\frac{6}{4+s}=4\] solve for s. (hint: reject negative root)
but it is less than 8 (4 up and 4 back again)
Im getting him......
Well, if you (are trying to) go upstream and can row at 4 mph. Current is rushing at you at 5.2 mph, you are going back at 1.2 mph, so you'll never get upstream. This has nothing to do with the 4 hours it takes to go up- and downstream.
if I scan his work, can you tell us where he went wrong?
it is not posting, it just hangs up
I scanned it as a different file type and it worked
He works well. Everything is correct, except he made a minor mistake at the very beginning. Knowing that he has to row upstream, we would expect that the current r should be less than 4. The first line should read 6(4-r)+6(4+r)=4(4-r)(4+r) and everything will turn out correctly.
THANK YOU!
You're welcome!
we ended up stuck again at 0=16-4r²
Divide by 4 on both sides: \[0=4-r^2\] add r^2 to both sides and take square-root \[r^2=4\] Let him try finishing the rest. (hint: reject negative root)
r=2
?
The answer is correct. Check the time it takes to do the return trip: 6/(4-2)+6/(4+2)=3+1=4 hours...ok
are you available to tell me if he got the right answer on the next problem?
A boat travels 6 miles per hour in still water. It travels 8 miles upstream and back again in 8 hours. what is the speed of the current? r=4.9
Correct to 1 decimal place. To be exact, it is \[2\sqrt{6}=4.899...\]
yes! he rounded up. Again thank you. nothing like having a bunch of math I cant do that must be done by tomorrow in order to pass the class! 2 down, 15 to go
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