Question

Integration:

Answer 1

\[\LARGE \int_{-1}^{0}~\frac{e^{1/x}}{x^3}~dx\]

Answer 2

sub u = 1/x

Answer 3

try letting u=1/x
so x=1/u

Answer 4

then do parts

Answer 5

Guys guys... In the eyes of god, mathematics doesn't exist! Now, let's all hold hands and pray.

Answer 6

yeah u can't avoid parts i think

Answer 7

mathematics is a language and God gave us languages

Answer 8

so shut your 3.14 hole

Answer 9

LOLOL ^

Answer 10

:)

Answer 11

\[\LARGE \int_{-1}^{0}~\frac{e^{1/x}}{x^3}~dx\]
\[\LARGE =\int_{-1}^{0}~\frac{1}{x}~e^{1/x}~\frac{1}{x^2}~dx\]
\(\Large u=1/x\) and \(\Large du=-\frac{1}{x^2}dx\)
\[\LARGE \int_{-1}^{0}~ue^udu\]
And then use parts like dan said?

Answer 12

*\[\LARGE -\int_{-1}^{0}~ue^udu\]

Answer 13

you should have an improper integral

Answer 14

\[\LARGE \LARGE \lim_{t \rightarrow 0} \int_{-1}^{t}~ue^udu~\]?

Answer 15

of x is between -1 and 0
and u=1/x