Question

I have a question about the digital communication course (i.e. 6.02). Could anyone provide some solutions to the assignments and/or exams? I have started working on the first assignment, but realized that without solutions to compare to, I can't tell if I'm understanding the subject matter or not.

Any help?

Answer 1

Well, the did not post them. If you don't see them on a web search, about my best solution would be to go over the question and your answer here and see if someone else has a different answer.

Answer 2

Great idea.

Let's try that out. My answer for problem set 1, problem 1: Information

http://ocw.mit.edu/courses/electrical-engineering-and-computer-science/6-02-introduction-to-eecs-ii-digital-communication-systems-fall-2012/assignments/MIT6_02F12_ps1.pdf

My answer is as follows:

Before we are told anything about Y, we have \[I = \log_{2} (1/(1/256)) = 8 bits\] of information about x. There are currently 256 equally possible outcomes for a random 8 bit binary number. When we are told Y, we find out exactly 4 of the 8 bits that constitutes X. This narrows our possibilities down to 16/256 outcomes, or 1/16.

Therefore, our final amount of information for X is \[I = \log_{2} (1/(1/16)) = 4 bits\]

Can anyone confirm my answer or prove me wrong?

Answer 3

@jagatuba did your classes cover this one?

Answer 4

@wio is another person that might know.