Question

help me i will medal

Answer 1

Carla conducted an experiment to determine if the there is a difference in mean body temperature for men and women. She found that the mean body temperature for men in the sample was 97.1 with a population standard deviation of 0.51 and the mean body temperature for women in the sample was 98.2 with a population standard deviation of 0.57.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 95% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.

Answer 2

@mathmate

Answer 3

@jigglypuff314

Answer 4

this is what i know:
The confidence interval for means depends on the standard error of the mean, SE = population SD divided by sqrt(number of samples making up the mean).

So the symmetric 95% confidence interval for each gender, men and women, will be [mean +- 1.96 SD/sqrt(number of samples)]

Answer 5

So what values are you missing from the problem?

Answer 6

I'm just confused from there on

Answer 7

i need to calculate the 95% ci and margin of error

Answer 8

So what is your sample size?

Answer 9

97.1 for men
98.2 for women

Answer 10

Those are the means.

Answer 11

so then whats the sample size

Answer 12

They haven't given that to you? Or a margin of error?

Answer 13

no.. all they gave me is above...

Answer 14

Carla conducted an experiment to determine if the there is a difference in mean body temperature for men and women. She found that the mean body temperature for men in the sample was 97.1 with a population standard deviation of 0.51 and the mean body temperature for women in the sample was 98.2 with a population standard deviation of 0.57.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 95% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.

Answer 15

Then just solve it without the sample size.

Answer 16

how

Answer 17

\[97.1\pm 1.96\times(0.51)\]

Answer 18

soo… 97.1 +- 0.99 ??

Answer 19

yup.

Answer 20

what about the other 1/2 of the question tho? it asked for margin of error and 95% ci

Answer 21

the margin of error for men is the .99 you calculated.

Answer 22

you do the same thing to calculate the m.o.e for the women

Answer 23

the CI for the women would be \[98.2\pm (1.96*.57)\]

Answer 24

so the m.o.e would be??

Answer 25

yes okay I get that now thank u 98.2 +- 1.11

Answer 26

got it!

Answer 27

do u know how to do the 95 % confidence interval

Answer 28

98.2±(1.96∗.57) = (97.0828, 99.3172)

Answer 29

That's your 95% CI for the women.

Answer 30

The confidence interval is the mean +- margin of error.

Answer 31

margin of error = z* x (std. error)

Answer 32

std. error = std. deviation / (sqr. root of sample size)

Answer 33

ohhhh okay so for men it would be 98.2 +- 1.11= what

Answer 34

That would be for women

Answer 35

Men would be 97.1 +- 0.99

Answer 36

ooooohh thank u

Answer 37

no problem!