Question

FAN AND MEDAL! simplify. the slash is in the because its a fraction

Answer 1

\[\sqrt[3]{7}\sqrt{7}/ \sqrt[6]{7^6}\]

Answer 2

@jim_thompson5910

Answer 3

@jdoe0001

Answer 4

\(\bf \large {\sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}}
\\\quad \\\\
\cfrac{\sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^6}}\implies \cfrac{\sqrt[3]{7\cdot 7}}{\sqrt[6]{7^6}}\implies \cfrac{\sqrt[3]{7^{\color{blue}{ 2}}}}{\sqrt[6]{7^{\color{blue}{ 6}}}}
\implies \cfrac{7^{\frac{{\color{blue}{ 2}}}{3}}}{7^{\frac{{\color{blue}{ 6}}}{6}}}
\\ \quad \\
\cfrac{7^{\frac{{\color{blue}{ 2}}}{3}}}{1}\cdot \cfrac{1}{7^{\frac{{\color{blue}{ 6}}}{6}}}\implies 7^{\frac{{\color{blue}{ 2}}}{3}}\cdot 7^{-\frac{{\color{blue}{ 6}}}{6}}\implies ? }\)

Answer 5

7^5/3?

Answer 6

hmm how did you get \(\bf 7^{5/3}\) ?

Answer 7

its the only one of my choices that has a fraction in it...

Answer 8

well... you're supposed to "solve" it, no pick choices

Answer 9

idk how to multiply fractions though

Answer 10

well... I assume this material has already being covered.... . you may want to brush up on your exponent rules -> http://www.math-play.com/image-exponents-rules.jpg

Answer 11

its 8:00pm and im really trying to hurry because I have ALOT due by midnight. can you just explain it briefly for me please?

Answer 12

@wolf1728 can you help?

Answer 13

my options are: 7^-1, 1, 7, and 7^5/3...so his thing is wrong eather wat because hes doing 7x7

Answer 14

@zepdrix

Answer 15

you seem to be trying to get to "a lot" at certain deadline
but you seem to be missing the idea behind the exercises at all :(

Answer 16

can we do it for you? yes
it is going to "help" you? nope

it'll simply be a disservice to you

we can "help" you understand it, yes
but you need to cover the material relevant to the section

Answer 17

I get the idea of it, to help me understand. but what I need is for you to help me with it. your thing is still gonna have 7x7 so it would be wrong.

Answer 18

\(\bf \large{\cfrac{7^{\frac{{\color{blue}{ 2}}}{3}}}{1}\cdot \cfrac{1}{7^{\frac{{\color{blue}{ 6}}}{6}}}\implies 7^{\frac{{\color{blue}{ 2}}}{3}}\cdot 7^{-\frac{{\color{blue}{ 6}}}{6}}
\\ \quad \\
\textit{exponent rule of }a^n\cdot a^m\implies a^{n+m}\qquad thus
\\ \quad \\
7^{\frac{{\color{blue}{ 2}}}{3}}\cdot 7^{-\frac{{\color{blue}{ 6}}}{6}}\implies 7^{\frac{{\color{blue}{ 2}}}{3}-\frac{{\color{blue}{ 6}}}{6}} }\)

Answer 19

same base, with whatever exponents, you'd add the exponents <--- exponents rule

Answer 20

ok so 7^-1/3?

Answer 21

yeap now keep in mind that \(\large \bf a^{-\frac{{\color{blue} n}}{{\color{red} m}}} =
\cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}} \implies \cfrac{1}{\sqrt[{\color{red} m}]{a^{\color{blue} n}}}\)

Answer 22

if your saying that 7^-1/3 is the answer then im sorry but your wrong.

Answer 23

\(\large \bf 7^{-\frac{1}{3}}\implies \cfrac{1}{7^{\frac{1}{3}}}\implies \cfrac{1}{\sqrt[3]{7}}\)

Answer 24

that's still wrong...

Answer 25

well... maybe the choices are off

but based on what you gave, that's proper

Answer 26

you can always just verify with your calculator

enter your original values, see what you get

enter that value, see what you get

Answer 27

how would I enter that into a calculator? if I could do that I wouldn't be on here

Answer 28

Maybe I'm oversimplifying but isn't
7^.33333333 * 7^.5 = 7^.8333333333333 ?
and the 6th root of 7^6 = 7 ?
Then 7^.8333333333333 / 7
= 5.0611401848 / 7 ?

= 0.7230200264 ?

Answer 29

:/ no....ill put the choices again
a) 7^-1
b) 1
C) 7
D) 7^5/3

Answer 30

hmm well. 1/3 wouldn't quite be equal to 0.3333 per se =)

Answer 31

well... I see the choices, none of them match

the result is proper "based on what you gave"

the issue I think is, you're basing yourself on the choices provided
they're helpful as a "guide", yes, they're not an authority

Answer 32

so all this and were nowhere

Answer 33

maybe your original material wasn't what we thought it was.. maybe a screenshot would help

Answer 34

the onlyl way I see 5/3 coming out is if you had 2/3 + 3/3 but that isn't the case

the 6/6 is at the denominator, thus it'd be negative

Answer 35

At least wouldn't it help to get a definite answer so then we can go back to see the correct method to DERIVE the answer?
Gee that is extreme backwards thinking isn't it?

Can we agree that the denominator is definitely 7 ?