Question

Help ???

Answer 1

What do you need help with?

Answer 2

Sorry, i'm not really sure how to do this. But here after a little searching this might be able to help you!
"Use the magnitude formula. The formula for the magnitude of vector v is |v| = sqrt(x^2 + y^2). Plug the values of the vector in this formula."

Answer 3

@Data_LG2 Can you help pretty please?

Answer 4

use the distance formula to calculate for the magnitude, do you know the distance formula?

Answer 5

Its D= x2-x1squ2 +y2-y1squ2

Answer 6

right :) substitute the points of A and B into the formula
\(\Large d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\Large |AB|=\sqrt{(3-(-5))^2+(1-3)^2}\)
tell me what you got and i'll check it

Answer 7

I got 4 and 64...

Answer 8

why did you get two values? It is looking for the magnitude not a point, so it should only have one value

Answer 9

oh so 68

Answer 10

can you show me your solution?

Answer 11

or 2 square root of 17

Answer 12

yep , that's right

Answer 13

yay okay can you help me with two more qs and id be finished??? Please?

Answer 14

*finished

Answer 15

first multiply the coordinates by two

Answer 16

I got -12 and 16

Answer 17

ok, then square each one of them

Answer 18

so i got 3.5 and 4

Answer 19

no, what i mean is "square" each of them not the square root
\((12)^2\ (16)^2\)

Answer 20

oh 144 and 256

Answer 21

After that, add them

Then get the square root of their sum

you are just basically doing this: \(|v|=\sqrt{(x)^2+(y)^2}\) :)

Answer 22

Omg thanks i got 20 :)

Answer 23

okay last one...please...

Answer 24

This one probably is the same as the one before. Use the distance formula to get t he magnitude

Answer 25

i did and i got 125

Answer 26

are you sure? can you show me your solution?

Answer 27

-5^2 + -10^2
25 +100= 125

Answer 28

yeah i made a mistake but im not sure where

Answer 29

\(\Large (4-6)^2 ?\)

Answer 30

also don't forget to get the square root

Answer 31

oh i got -10 when i was supposed to get -2 huh

Answer 32

it's alright everybody make mistakes ;)

so what would be the right answer?

Answer 33

Square root 29

Answer 34

right

Answer 35

Yay! Thanks so much! :)

Answer 36

Always remember that if you are looking for the \(\Large \color{red}{magnitude}\) of:

•two points, use the distance formula : \(\Large \color{blue}{|d|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\)
•a vector, use the Pythagorean theorem: \(\Large \color{blue}{|v|=\sqrt{(x)^2+(y)^2}}\)

your welcome (^_^)

Answer 37

Thank you :)