Question

Help

Answer 1

Find the equation of the circle that is shifted 5 units to the left and 2 units down from the circle with the equation \[x^{2}+y^2=19\]

Answer 2

well, I'll help you with this one too! Okay so, in the last question it was the coordinates of the middle of the circle were the a and b values, so in this question it would appear that you have 0,0 as the middle of your circle.

Answer 3

this would mean shifting 5 units left and 2 down would make the middle of the circle (-5,-2), or (x--5)^2+(y--2)^2=19

Answer 4

so (x+5)^2+(y+2)^2=19

Answer 5

so (x-5)^2(y-2)^2=19

Answer 6

http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php this link helped me understand it

Answer 7

oh ok lol same answer i got

Answer 8

you forgot the plus in the middle, and it is automatically x-a and y-b so you would do x--a if it is negative, or y--b if it is negative.

Answer 9

you just gotta swap the signs.

Answer 10

right i got this (x+5)^2+(y+2)^2=19 sorry didnt finish explaining

Answer 11

right :) ya that is correct, nice

Answer 12

thanks again!

Answer 13

no problem :)