A plank of length L=1.800 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at the other end as shown. The cable is attached at a height H=1.70 m above the pivot and the plank's CM is located a distance d=0.600 m from the pivot.

Calculate the tension in the cable.

Question

A plank of length L=1.800 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at the other end as shown. The cable is attached at a height H=1.70 m above the pivot and the plank's CM is located a distance d=0.600 m from the pivot. 

Calculate the tension in the cable.

anonymous · Answer

So lets start by finding the length of the cable.
d= $$\sqrt{1.8^2+1.7^2}$$
d=2.48

Now let T represent Tension
mgd1-T(H/d2)l
4(9.81)(.6)-T(1.7/2.48)1.8=0
23.544=1.2T
T=19.62N

I'm pretty sure this is how you go about solving for tension!

anonymous · Answer

thats what I got too! But its telling me its wrong :(

anonymous · Answer

Oh wait I think we just calculated wrong! Thank you so much for explaining to me! :)