Question

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s11_qp_12.pdf
Q11

Answer 1

AlCx+H2O-->CxHy
CxHy+x+y/4O2-->xCO2+y/2H2O
72/1000=number of moles *24
number of moles=3*10^-3
3*10^-3=y/2
y=6*10^-3
6*10^-3/4+x
x=1.5*10^-3
We conclude here that the gas is methane after balancing by divide by the smallest figure
subsitute the values of x and y we get a ratio of O2 to CO2 and H2O of 2:1:2
ln Equation 1 3*10^-3=0.144/x*(27+12)
0.144=0.117x
x=1.2303769
39*x=48
this represent 4 carbon

Answer 2

is this method right?

Answer 3

i hate trying out all options of the question

Answer 4

the method is fine i think, i'm not sure about your calculations

Answer 5

but is their any other method instead of trying out all compounds given in the question

Answer 6

is this right 3*10^-3*12=0.036 grams
0.144-0.036=0.108 grams
0.108/27=4*10^-3
Ratio 4:3

Answer 7

So the answer must be Al4Cl3

Answer 8

i don't get this T_T