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lim (3)/(y+4) y --> -infinity
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y is approaching negative infinity so y+4 is also approaching negative infinity
the denominator is some number that keeps getting larger and larger in the negative direction
\[\lim_{y \rightarrow - \infty }\frac{ 3 }{ y+4 }=\lim_{y \rightarrow - \infty }\frac{ \frac{ 3 }{ y } }{ 1+\frac{ 4 }{ y }}=\frac{ 0 }{ 1+0 }=0\]
Thanks!!
yw
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