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Find a formula for f(x) f(2) = (1/2)^0 +(1/2)^1 + (1/2)^2 = 1+ 1/2+1/4=7/4
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What is the original function?
I can't understand the question
let f(x) be a function that adds the first x powers of 1/2 and then find the function with this given info.
Let f(x) be a function that adds the first x powers of 1/2: f(x) = (1/2)^0 = 1 f(1) = (1/2)^0 + (1/2)^1 = 1+1/2 =3/2 f(2) = (1/2)^0 +(1/2)^1 + (1/2)^2 = 1+ 1/2+1/4=7/4
Is this supposed to go on to infinity? i.e \[\sum_{x=0}^{\infty}\left( \frac{1}{2}\right)^x \]
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how do i express that in terms of f(x) ?
maybe you could use a recursive definition \( f(x_0)=1/2\\ f(x_n)=f(x_{n-1})+1/2\)
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