Mathematics
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OpenStudy (anonymous):
Find the exact value of sin75 using any appropriate formulas.
help please :D
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OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@Loser66
OpenStudy (anonymous):
sin75 is the same as sin(45+30)
OpenStudy (anonymous):
from there you do sin30*cos45+cos30*sin45
OpenStudy (anonymous):
oh ok
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OpenStudy (anonymous):
which if you find those coordinates
= \[1/2 * \sqrt{2}/2 + \sqrt{3}/2 * \sqrt{2}/2\]
OpenStudy (anonymous):
= \[\sqrt{2}/4+\sqrt{6}/4\]
OpenStudy (anonymous):
ty so much
OpenStudy (anonymous):
can u help with another question?
OpenStudy (anonymous):
combine you get \[(\sqrt{2} + \sqrt{6})/\]
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OpenStudy (anonymous):
/4
OpenStudy (anonymous):
sure thing and ya i can help
OpenStudy (anonymous):
find the exact value of [\sec ^{2}(2\pi/3)+\tan(5\pi/4)(\cos \pi/3)\]
OpenStudy (anonymous):
ah crap let me re write it
OpenStudy (anonymous):
haha sure thing
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OpenStudy (anonymous):
\[\sec ^{2}(2\pi/3)+\tan(5\pi/4)(\cos \pi/3)\]
OpenStudy (anonymous):
finally lol
OpenStudy (anonymous):
haha ok gimme a sec to figure out how to do it and then how to explain it XD
OpenStudy (anonymous):
no problem :D
OpenStudy (anonymous):
are you trying to find the # value or just simplify it?
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OpenStudy (anonymous):
because sec^2(2pi/3) = 4
OpenStudy (anonymous):
it says find the exact value
OpenStudy (anonymous):
i know the answer but idk how to get it
OpenStudy (anonymous):
the answer is 4.5
OpenStudy (anonymous):
ok well then the other half =.5 then XD ok.....so to solve the first part....gimme sec to type this out
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OpenStudy (anonymous):
sec^2(2pi/3) is the same as saying (sec(2pi/3))^2
OpenStudy (anonymous):
would i have to jsut type all this into a calculator?
OpenStudy (anonymous):
that you can then change to (1/cos(pi/3)^2
OpenStudy (anonymous):
im sure you could but its fine, i can just explain it here
OpenStudy (anonymous):
cos(pi/3)= 1/2 so you have (1/1/2)^2 = (2)^2 = 4
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OpenStudy (anonymous):
yea i think i understand this now haha
OpenStudy (anonymous):
i got one more if you are up for it :D
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
solve for x to the nearest degree over 0<x<360 in the equation \[4\cos x-3secx=2\]
OpenStudy (anonymous):
you are suppose to multiply by cosx right?
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OpenStudy (anonymous):
and get \[4\cos ^{2}x-3=\]
OpenStudy (anonymous):
2cosx
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
i get stuck here on what to do next
OpenStudy (anonymous):
ok...let me see.....
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OpenStudy (anonymous):
here, one sec ill be right back
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
ok so, im double checking, but i got undefined as my answer....
OpenStudy (anonymous):
the answer key says its 131 and 229
OpenStudy (anonymous):
but i coudlnt get an answer either so idk
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OpenStudy (anonymous):
sorry.