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Calculate the pH of a solution made by mixing equal volumes of a solution of NaOH with a pH of 11.40 and a solution of KOH with a pH of 10.30. (Assume the volumes are additive.)
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I haven't done these types of problems in a while, but I am going to give it a try. Since you have two equally strong bases, you can simply assume they both dissociate completely. So, find the concentrations of each base, and then take the negative log of their new concentration.
You have, pH, remember that you want [OH] for this base.
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