Question

solve this determinant

Answer 1

@ganeshie8 ?

Answer 2

@mathslover ?

Answer 3

@Hero ?

Answer 4

I would say use the condensation method, but that would be too tedious.

Answer 5

very tedious!!

Answer 6

if we take 1/z^2 common from 1st row
and 1/x^2 from second row
and 1/x^2*z^2 from third row

Answer 7

will it simplify the calculation?

Answer 8

@ParthKohli ?

Answer 9

@iambatman ?

Answer 10

@dan815 ?

Answer 11

Your approach seems like a pretty good idea.

Answer 12

cant simplify it further what to do ?

Answer 13

Once you've simplified it as much as you can, you should be able to use condensation method more conveniently.

Answer 14

@Loser66 ?

Answer 15

@Miracrown ?

Answer 16

@aajugdar ?

Answer 17

determinant :O

Answer 18

are you supposed to find values of x,y,z?

Answer 19

or just solve it

Answer 20

just solve it

Answer 21

and write final equation

Answer 22

then then whats the prob

Answer 23

yes

Answer 24

the expansion is too long

Answer 25

take 1/z out of first row
then 1/x out of 2nd
1/xz out of third

Answer 26

ya thats what i did

Answer 27

1/z^2 common from 1st row
and 1/x^2 from second row
and 1/x^2*z^2 from third row

Answer 28

not sqeure term
do u c all the terms in power?
how can you take squere out

Answer 29

It's a bit tedious but it can be done

Answer 30

yes

Answer 31

will it be easy if we do not take out square?

Answer 32

solve it now

Answer 33

still it long :P

Answer 34

@aajugdar

Answer 35

@aajugdar

Answer 36

hah
whats wrong with this one

Answer 37

i doubt you will be able to simplify it more
so u will hv to solve as it is now

Answer 38

please try once

Answer 39

.-.

Answer 40

?

Answer 41

i have not seen a matrice of such proportions in a while now

Answer 42

?

Answer 43

With some judicious factoring, some of which has been mentioned before, we have:

\(\dfrac{z+y}{z^{3}}\cdot\dfrac{x+y}{x^{3}}\cdot\left|\begin{matrix}\dfrac{-x}{y+z} & 1 & 1 \\ 1 & 1 & \dfrac{-z}{x+y}\\ y & x+2y+z & y\end{matrix}\right| = 0\)

Sure, it's a little tedious, but go ahead and stick to it until you get it!

Answer 44

lol just solve it dude
will take atmost 5 mins