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Verify the identity. cot ( theta - pi / 2 ) = - tan theta
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I know cos(theta)+sin(1)= Sin(theta)
Working with Sin(theta-pi/2)
See enclosed
I see. I was researching problem further and found this \[\sin(\theta-\pi/2)=\sin(\theta)\cos(\pi/2)-\cos \theta \sin (\pi/2)\]........... Question from where did the \[\cos(\pi/2) \] by itself come from in the second half of the equation.
This is a standard trigonometric identity sin(A-B)=sin(A)cos(B)-cos(A)sin(B)
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Thank you!!
this was an angle sum and difference identity. I get it now.
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